2y^2-5y+4=0

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Solution for 2y^2-5y+4=0 equation:


Simplifying
2y2 + -5y + 4 = 0

Reorder the terms:
4 + -5y + 2y2 = 0

Solving
4 + -5y + 2y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
2 the coefficient of the squared term: 

Divide each side by '2'.
2 + -2.5y + y2 = 0

Move the constant term to the right:

Add '-2' to each side of the equation.
2 + -2.5y + -2 + y2 = 0 + -2

Reorder the terms:
2 + -2 + -2.5y + y2 = 0 + -2

Combine like terms: 2 + -2 = 0
0 + -2.5y + y2 = 0 + -2
-2.5y + y2 = 0 + -2

Combine like terms: 0 + -2 = -2
-2.5y + y2 = -2

The y term is -2.5y.  Take half its coefficient (-1.25).
Square it (1.5625) and add it to both sides.

Add '1.5625' to each side of the equation.
-2.5y + 1.5625 + y2 = -2 + 1.5625

Reorder the terms:
1.5625 + -2.5y + y2 = -2 + 1.5625

Combine like terms: -2 + 1.5625 = -0.4375
1.5625 + -2.5y + y2 = -0.4375

Factor a perfect square on the left side:
(y + -1.25)(y + -1.25) = -0.4375

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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